CNC_0002
MAKE: Workbench -
Y-axis - Assembly![]()
Preliminary Considerations:
Recommended minimum possible move distance is 0.0001", which is 0.000254 cm, which is 0.00254 mm.
Using a pitch of 5 mm means that the rotation for a linear movement of 0.00254 mm is 5 / 0.00254 = 1968.5 increment (i.e. 2000 pulses per revolution encoder)
Desired maximum jog speed = 0.25 m/s = 250 mm/s. This is 250 / 5 = 50 rps
50 rps * 2,000 pulses per revolution = 100,000 pulses per second
25,000 unit/sec / 50 rps requires an encoder with 500+ pulses per revolution.
The maximum motor speed (Continuous: - No-load: - Full Speed) of a motor that is direct-coupled to the screw is 50 rps = 3,000 rpm
Or in other words; at 25.000 units/sec * 0.00254 mm = 63. 5 mm / sec 2.5" per sec at recommended minimum possible move distance.
Or; at 45.000 units/sec * 0.00254 mm = 63. 5 mm / sec 4.5" per sec at recommended minimum possible move distance,
It appears that the minimum possible move distance must be increase, or maximum jog speed reduced, or some combination of the two.
I think that the following does not provide any headroom. Perhaps headroom is only need while the motor is in the 'rated state.
![]()
Initial Perceived Requirements:
See note on
______________________
A short answer from arvidb on CNCzone;- "For a smaller wood and plastic cutting machine (and maybe - maybe! some light aluminum), several people on CNCzone seam to have had success with 100-200 oz-in (0.7 - 1.4 Nm) stepper motors direct driving a 5 turns/inch (5 mm lead) ACME (trapezoidal) screw.
![]()
Purchased Items:
Linear Positioning Table ~ Item # CNC 0013: This is the one for the y-axis.
Linear Positioning Table ~ Item # CNC 0014: Alternative
![]()
![]()
![]()
Screw:
Reduction Ratio:
Acceleration and Deceleration:
Not done yet. If the travel speeds are not exceptionally fast then the acceleration and deceleration should not be a concern.
Power Required:
Screw Efficiency = Ball screw (η) = 0.9
Torque (Q) at the Screw = Force * (Screw lead / (2 * 3.1428)) * (1 / Screw efficiency (η))
= 200 N * (0.005 m / (2 * 3.1428)) * (1 / 0.9 [ball screw])
= 0.17677 Nm
Torque (Q) at the Motor = Torque at the Screw / Reduction Ratio
= 0.17677 Nm / 1 (secondary reduction) = 0.17677 Nm
Power Output (P) [in CNC context] = Force * Speed, Torque * Rotational speed, or voltage * Current
= 0.17677 Nm * (3000 rpm / 60) * 2 * pi = 55.6 W = (55.6 / 735) = 0.076 hp
For friction (transmission, ??) and motor loss 10% etc. increase by 50% = 83.4 W = (83.4 / 735) = 0.113 hp
Related Miscellaneous Note:
![]()
Back to top | SynchroLite Home Page | UniCopter Home Page | Nemesis Home Page
Last Revised: January 6, 2007