Item 1489
DESIGN: Single-Bladed All Electric Rotor
- Disk - Forces & Moments![]()
Objective:
To determine the forces and moments at work on the rotor.
Reference:
DESIGN: SynchroLite ~ Rotor - Disk - Centers, Radii & Moments![]()
Symbols:
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Symbol: |
Name: |
Definition: |
Units: |
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T |
Thrust |
Thrust |
pounds |
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L |
Lift |
Vertical component of Thrust |
pounds |
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P |
Pull |
Horizontal component of Thrust |
pounds |
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CF |
Centrifugal Force |
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C |
Centroid |
Center of mass |
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M |
Moment |
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D |
Drag |
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pounds |
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CM |
Moment of centrifugal force |
Restoring moment of centrifugal force |
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WA |
Weight Arm |
Moment arm from teetering hinge to centroid |
feet |
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TA |
Thrust Arm |
Moment arm from teetering hinge to ctr. of lift |
feet |
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W |
Weight |
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pounds |
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GW |
Gross Weight |
Gross weight of craft |
pounds |
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RRPM |
Rotor speed |
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rpm |
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Ω |
Rotor speed |
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radians |
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B |
Teeter angle |
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degrees |
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R |
Restoring force |
The restoring force of the centrifugal force |
lb-ft |
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Subscripts: |
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Designated on drawing by preceding dash |
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b |
Blade |
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cw |
Counter Weight |
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hov |
Hover |
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max |
Maximum teeter |
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min |
Minimum teeter |
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f |
Fuselage |
Gross weight less weight of rotors |
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t |
Total |
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h |
Hub |
Hub excluding blades |
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ind |
Induced - (drag & thrust) |
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pro |
Profile (drag) |
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Thrust and Centrifugal Force:
The 2-blade rotor is only for temporary reference and CF forces in the second and third drawings must be changed.
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Algorithms and Calculations:
The following is just approximations, at present, to get a feel for the requirements.|
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W b |
10 lbs. |
Value from ~ SynchroLite 3-rotor is 21# for 550 GW |
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W cw |
20 lbs. |
Arbitrarily set at half that of the blade's arm. |
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WA b |
4.5 ft. |
Tapered blade with 10 foot radius |
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WA cw |
2.25 ft. |
(10 lbs / 20 lbs ) * 4.5 ft. |
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Item: |
Value: |
Notes: |
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GW |
550 lbs. |
254# craft + 296# load |
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CF b |
5,731 pounds |
Centrifugal force of blade |
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CF cw |
5,731 pounds |
Centrifugal force of counterweight |
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β hov |
2.5º |
Tan(A) = a/b = 550/(6368 + 6368) Angle = 2.5º |
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T hov |
551 lbs. |
c = b/ cos(A) = 550/cos(2.5) = 551 lbs |
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P hov |
24 lbs. |
a = tan(A) * b = 0.0437 * 550 = 24 lbs |
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β max |
14.5º |
Maximum Teetering angle = 2.5º + 12º = 14.5º |
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T max |
568 lbs. |
c = b/ cos(A) = 550/cos1(4.5) = 568 lbs |
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P max |
24 lbs. |
a = tan(A) * b = 0.2586 * 550 = 142 lbs |
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β min |
-9.5º |
Minimum Teetering angle = 2.5º - 12º = -9.5º |
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T min |
568 lbs. |
c = b/ cos(A) = 550/cos(-10.5) = 559 lbs |
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P min |
24 lbs. |
a = tan(A) * b = -0.1853 * 550 = -102 lbs |
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Drag and Centrifugal Force:
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Related Pages:
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Initially displayed: January 9, 2006 ~ Posted on PPRuNe; January 11, 2006; on Rotary Wing Forum; January 9, 2006
~ Last Revised: Friday, February 3, 2006The above utility invention is openly and publicly disclosed on the Internet to negate an entity from patenting it, to the exclusion of all others whom may wish to use it. ~ Reference patent law 35 U.S.C. 102 A person shall be entitled to a patent unless - (a) the invention was known ... by others in this country, ..., before the invention thereof by the applicant for patent.