Item 0904
DESIGN: UniCopter ~
Dimension, Area & Drag - Drag - In Forward Flight![]()
From calculations in Helicopter Performance, Stability and Control, chapter 4 & page 306
Much of the following is in:
See Access database: FORM: Trim for calculations.Get info from Hub Drag, Rotor-Wing Aerodynamics, book 2, page 66
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Reducing Drag:
Forward flight:
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The rotor hubs, blades, tail booms and fuselage will have detrimental effect on the flow of 'clean' air to the upper quadrant of the propeller.
Potential Solution;
Improved Airflow to Prop:
The jackshaft from the soft start to the rotor's mid-gearbox could have universal joints at both ends to get the sheave closer to the prop shaft. Similar to the drive shaft in a car. If the jackshaft had a sliding spline then the vibration of the engine would not effect the rotor drive train.
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Fuselage:
In fast forward flight, the UniCopter will have a slight nose-down pitch. This combined with the downwash from the rotor may mean that the plan profile of the fuselage should be considered, as well.
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Total Frontal Area: (
AF) = 8.31 sq-ft.; from DESIGN: UniCopter ~ Dimension, Area & Drag - View - Front, Y-Z planeCoefficients of Drag: (CDF); from OTHER: Aerodynamic - Drag - Parasite , [Source ~ RWP1 figure 4.17]
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Rotorhubs:
For general interest overview see;
http://www.cartercopters.com/gt-hub_drag-compatible_14.htmlThe rotor hubs are 1.25 sq-ft, of frontal area; from
DESIGN: UniCopter ~ Dimension, Area & Drag - View - Front, Y-Z planeCoefficient of Drag for Fuselage - rotor hub: (
CDR) = 0.5 My guess from OTHER: Aerodynamic - Drag - Parasite , [Source ~ RWP1 figure 4.17]Equivalent flat plate area of rotor hubs
fR = AR * CDR = 1.25 * 0.5 = 0.625 ft2![]()
Landing Gear:
Frontal Area: (
ALG) = 0.2 sq-ft. Currently a guess. Will be from DESIGN: UniCopter ~ Dimension, Area & Drag - View - Front, Y-Z planeCoefficient of Drag for Fuselage: (
CDLG) = 0.7 My guess from OTHER: Aerodynamic - Drag - Parasite , [Source ~ RWP1 figure 4.26]Equivalent flat plate area
fLG = ALG * CDLG = 0.2 * 0.7 = 0.14 ft2See also:
DESIGN: Unicopter ~ Landing Gear![]()
Horizontal Stabilizer:
Area: (
AH) = 3 sq-ftSpan: (
bH) = 4 ft.Aspect Ratio: (
A.R.) = b2H/AH = 5.333Thickness Ratio: (
t/c) = 0.12 NACA 0012 at presentMean Aerodynamic Chord: (
MAC) = 0.75 ft.Reynolds number at 115 knots =
RN = c x MPH x 9360 = 0.75 ft.x 132 mph x 9360. = 926,640Estimate (
CDO) from OTHER: Aerodynamic - Drag - Parasite, [Source ~ RWP1 figure 4.15] = 0.01Estimate (
CLH) from trim conditions OTHER: Aerodynamic - Drag - Parasite, [Source ~ RWP1 chapter 8] = 0.6Estimate
span efficiency factor (δ) = 1Calculate induced drag coeff. (
CDi) = (CLH2 * (1 + δ)) / (π * A.R.) = (0.62 * (1 + 1))/(3.143 * 5.333) = 0.043Calculate root thickness (
t) = 0.12 * 1 ft. = 0.12 ft.Estimate junction drag coeff., (
CDJ) from 0898.html, [Source ~ RWP1 figure 4.21] = 0.1Compute equiv. junction drag coeff.
(CDJ equiv) = 2(CDJ * (t2)/ AH) = 2 * ((0.1 * 0.12 * 0.12) / 3) = 0.0001Total drag coeff.
CDH = CDO + CDi + CDJ equiv = 0.01 + 0.043 + 0.0001 = 0.0531Estimate
qH/q = 1Calculate (
fH) = (qH/q)* (CDH * AH) = 1 * 0.0531 * 3 = 0.159 ft2![]()
Horizontal Stabilizer:
Negative lift - this has nothing to do with drag but it has to do with longitudinal static stabilitySee: DESIGN: UniCopter ~ Trim, Stability & Control - Trim - Horizontal Stabilizer
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Vertical Stabilizer:
Area: (
AV) = 3.25 sq-ft.Thickness Ratio: (
t/c) = 0.12 NACA 0012 at presentMean Aerodynamic Chord: (
MAC) = 16"Reynolds number at 115 knots =
RN = c x MPH x 9360 = 1.33 ft.x 132 mph x 9360. = 1,600.000Estimate (
CDO) from OTHER: Aerodynamic - Drag - Parasite, [Source ~ RWP1 figure 4.15] = 0.01Estimate
qV/q = 1Calculate (
fV) = (qV/q)* (CDV * AV) = 1 * 0.01 * 3.25 = 0.0325 ft2 ![]()
Main Rotors:
Get info from Hub Drag, Rotor-Wing Aerodynamics, book 2, page 66. Note that hub drag is currently included above in Fuselage.
H-force:
OTHER: Aerodynamics - Drag - H-force
Reverse Air Flow:
If the RRPM is 480, the disc radius is 9'-6" and the forward speed is 150 kts (173 mph), the radius of zero flow at 270º azimuth is 5'-0"". The combined velocity at azimuth 90 and r = 29" / 2 (ie. the craft's longitudinal centerline) = 14.5" R will therefor be 315 fps (215 mph). This probably indicates that, when fairing the rotor hubs, the attention should be directed toward the advancing sides. See: FORM: Tangential Velocity.
Blades:
Consider clading the root of the blades out to the centerline of the craft so that they have a 'D' x-section, with the flat portion on the bottom. From azimuth 20º to 130º approximately this flat portion will just clear the fuselage. From the center of the craft out to about the center of the other hub, this shape will start transitioning from the 'D' to an ellipse.
Crazy Idea :
The final drive shafts up to the hubs will probably be tubes. If the hub's top caps have a hole in their centers then it may be possible to locate non-rotating sheets between the top of each hub and the other rotor's blades, or provide a low profile axes that are inboard of the rotors axes.
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Propeller:
Must consider drag during powered forward flight and during autorotation, regarding any change in pitch.
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Vectored Exhaust & Cooling:
No effect during autorotation.![]()
Total Equivalent Flat Plate Area:
(f)|
|
|
Area: (1) |
Drag Coefficient: (2) |
Equivalent Flat Plate Area: [f] |
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Fuselage |
8.25 ft2 |
0.23 (3) |
1.30 ft2 |
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|
Rotorhubs |
1.25 ft2 |
0.5 |
0.625 ft2 |
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|
Landing Gear |
0.2 ft2 |
0.7 |
0.14 ft2 |
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Vertical Stabilizer |
ft2 |
|
0.0325 ft2 |
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Horizontal Stabilizer |
ft2 |
|
0.159 ft2 |
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|
H.S. Lift (downward ) |
ft2 |
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|
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Sub Total: |
2.26 ft2 |
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Roughness & Leakage |
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|
0.1 ft2 |
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Protuberances |
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|
0.15 ft2 |
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Cooling Losses |
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0.01 ft2 |
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Total: |
2.5 approx.? |
This data is used in
DESIGN: UniCopter ~ Dimension, Area & Drag - Drag - Parasitic, in Forward Flight ~ Calculations![]()
Rough & wild
Notes: on Pitching Momentum, (to be moved (possibly to 0902) & cleaned up)For an airplane wing: LW = (ρ / 2) * V2 * S * CL . Where S is the area of the wing.
For an airplane wing: LW = (0.002377 [slug/ft3] / 2) * V2 * 3 [ft2] * CL . Where S is the area of the wing.
0.002377 @ ISA)
slug/ft3
-2.75ft2 - ft. / 3.0 ft2 - ft. = 0.916
Cl of -0.916 with a NACA 0012 airfoil is a Angle of attack of -8 degrees
Cl of -2.337 with a Wortmann FX 74 CL5-140 airfoil is a Angle of attack of -8 degrees
Cl of --0.916 with a Wortmann FX 74 CL5-140 airfoil is a Angle of attack of +4.5 degrees
IT, INITIALLY, LOOKS LIKE THE WORTMANN HAS MORE (LIFT) AT 0 DEGREES THAN IS EVEN NEEDED!!!!
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A crude initial attempt to see if the craft, at its maximum obtainable speed will be at a nose down angle sufficient enough to cause the H.S. to stall and the craft to tumble.
For the fun of it & probably totally wrong
Assume a forward tilt on the rotors and craft of 5º
Assume a gross weight of 1150 pounds
The lift component must be 1150 pounds.
The forward component must be tan(10) * 1150 = 101 pounds.
The following algorithm is from page B319
F = 1/2 ρ C
D A v2v2 = F / (1/2 ρ CD A)
v2 = 101 / (1/2 * 0.002377 slugs/foot3 * 1.57 )
v2 = 101 / 0.0018677
v2 = 53,897
v = 232 ft/sec
v = 158 miles per hour | 137 knots
This does not include the H-force drag of the rotors.
This is based on the frontal area only whereas at 5-degrees pitch down there will be more drag
Where
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An Alternate Rough Calculation of Maximum Forward Speed:
from [Source ~ RWP5 p.30]Max Speed = 41 * cubic root( 30 min rating of engine / equiv. flat plate area)
Max speed = 41 * cubic root(124 hp / 1.66)
Max speed = 172 knots (198 mph)
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Possibly Relevant Outside Web Pages:
John D. Berry, Unsteady Velocity Measurement Taken Behind a Model Helicopter Rotor Hub in Foward Flight , NASA TM-4738, March 1997 , pp. 246, (8MB).
http://techreports.larc.nasa.gov/ltrs/dublincore/1997/tm/NASA-97-tm4738.html ![]()
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Last Revised: March 11, 2007