Item 0871
DESIGN:
UniCopter ~ Rotor - Disk - Lateral Dissymmetry of Lift and Drag? - (3-blades)Review 1073.html in Obsolete folder to see if these two pages are in agreement
Overview:
Evaluation of the oscillating rolling moments with two 3-blade really rigid rotors, during forward flight, caused by dissymmetry of lift.
Conclusion:
There will be vibration, with 3-blade rotors. The side of the helicopter that has the advancing blade located at 90º azimuth will have greater lift than the other side where the advancing blades are at 30º and 150º azimuth. This is irrespective of whether the rotation is outside-forward or inside-forward.
Potential Solutions:
Evaluation of the oscillating yawing moments during forward flight, caused by the dissymmetry of H-force drag, may be later considered on a separate web page.
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Drawing of Lateral Moment Arms of a Single Rotor:

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Hover:
Moment on Y-Y:
(100 lbs. * 1.0) = (2 * ( 100 lbs. * .5))If all three blades are providing an equal amount of lift then the center of the lift will be at the centerline of the disk.
Brilliant; I didn't need a drawing to prove this._____________________________
Perhaps the significance of this is that if the center of lift is behind the centerline of the blade's pitch axis then the blades will be imparting a loading on the pitch arms. During hover, there should be no cyclic oscillation because the sum of the moments of the three blades should equal zero. There will be a force on the collective.
The center of lift on the VR7 blade varies from 41% of chord at Alpha = 0º to 29.3% of chord at Alpha = 12º.
This page was done to assure that the wheels in the 'swash-ring' are always in contact with the same flange of the ring and therefore not having to change their direction of rotation ( at 600 RRPM) 40 times per second.
They will contact both flanges if Higher Harmonic Control is implemented. See swishring with revision for one torus with a follower on the top and a follower on the bottom.![]()
Forward Flight: (Lateral Dissymmetry of Lift and Drag)

I think that the single advancing blade at 90º azimuth will have a greater thrust than the other rotor's two advancing blades which will be at 30º and 150º azimuth, Note the moment arm lengths and the air velocity. This will cause a rotational vibration about the longitudinal axis (roll).
Higher Harmonic Control will allow the lift at 30º and 150º azimuth to be increase somewhat and the lift at 90º azimuth to be decrease somewhat.Flight-Control Solution:
Consider adjusting HHC pitch by a spring steel 'warpable'
The 1P will involve frequent changes, as the cyclic stick is moved. Changes to the HHC will be gradual and infrequent, relative to the primary control, since it is controlled by the forward velocity of the craft. The 3P control may be similar to the
SynchroLite's Opposed Lateral Cyclic. For possible means of flight control, see DESIGN: UniCopter ~ Control - Flight - Swishring - Fixed Azimuth OverviewRe Drag
: An airfoil that has a higher cl/cd than another should have a lower dissymmetry of drag for a given lift.![]()
Calculations: by
FORM: Lateral Dissymmetry ~ UniCopterDefault Values:
Slope of lift chord: a = 6.0 / radian
Vertical velocity in hover: v1 = 25 fps
Density: ρ = 0.002377 slug/ft3 @ ISA
Rotor: Ω = 600 RPM
Radius: r = 0.75 * 8.33 = 6.2475 feet
Chord: c = 0.666 feet
Blade segment Δr = (8.33 / 10) = 0.833 feet
Collective = 5.5º
Inputs:
Collective: θ0
1P Blade Pitch
θ1P, Azimuth of input blade pitch: Ψ1P.Higher harmonic 3P blade pitch:
θ3P.Forward Velocity:
VCyclic amplitude:
θ1PCyclic amplitude azimuth:
Ψ1P3rd harmonic amplitude:
θ3PAlgorithims:
Tangential (local) Velocity: U = (Ω * r) + V * sin(Ψ * ( π / 180) [ft/sec]
Inflow Angle: φ = v1 / (U) [radians]
Cyclic amplitude at azimuth: θ1P@Ψ = θ1P * sin(Ψ1P) This will have to be checked.
3rd harmonic amplitude at azimuth:
θ3P@Ψ = θ3P * sin(Ψ * 3) This will have to be checked.Blade Pitch:
θ = θ1P@Ψ + θ3P@ΨBlade Pitch:
θ = ά + φ [radians]Angle of Attack:
ά = θ - φ [radians]Lift [
L]:An aerodynamic force caused by air flowing over an airfoil. The vertical component of thrust.
For an airplane wing:
LW = (ρ / 2) * V2 * CL * S . Where S is the area of the wing.
ΔL = (ρ / 2) * (Ω * r)
2 * a(θ - (v1 / (Ω * r)) * c * ΔrΔL = (ρ / 2) * (U)
2 * a(θ - (v1 / U)) * c * ΔrΔL = (ρ / 2) * (U)
2 * a(θ - φ) * c * ΔrΔL = (
0.002377 / 2) * (U)2 * a(θ - φ) * 0.666 * 0.833ΔL =
0.001188 * (U)2 * a(θ - φ) * 0.666 * 0.833L = (U)2
* a(θ - φ) * 0.000659
Thoughts on coding:
Base calculations on r = .75R at all azimuths, even though it will be greater on the retreating side.
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FORM: Lateral Dissymmetry ~ UniCopter
The following values assume that the rotor disks have no forward pitch and all the forward thrust is coming from a pusher propeller.
The following thrust values are only for the blade segment at .75R of a helicopter weighing 750 lb GW and are probably not representative of the whole blade.
MPH:
| Collective: | 3P amplitude: | Blade Segment Thrust @ .75R at Noted Azimuth and Rotor: | Moments: | Total Lift:|
MPH: |
θ 0 |
θ 3P |
90º |
Port |
30º |
Star |
150º |
Star |
270º |
Star |
210º |
Port |
330º |
Port |
PORT |
STAR |
Total Lift: |
||||||||||||||||||||||||||||||||||||||||||
|
|
|
|
lbs |
lb-ft |
lbs |
lb-ft |
lb |
lb-ft |
lbs |
lb-ft |
lbs |
lb-ft |
lbs |
lb-ft |
Port |
Star |
|
||||||||||||||||||||||||||||||||||||||||||
|
0 |
5.5 |
0 |
58 |
427 |
58 |
246 |
58 |
246 |
58 |
-296 |
58 |
-116 |
58 |
-116 |
724 |
723 |
348 |
||||||||||||||||||||||||||||||||||||||||||
|
50 |
5.4 |
0.1 |
79 |
580 |
69 |
294 |
69 |
294 |
38 |
-195 |
46 |
-92 |
46 |
-92 |
772 |
775 |
347 |
||||||||||||||||||||||||||||||||||||||||||
|
100 |
5.1 |
0.3 |
95 |
704 |
80 |
341 |
80 |
341 |
22 |
-113 |
33 |
-67 |
33 |
-67 |
816 |
817 |
343 |
||||||||||||||||||||||||||||||||||||||||||
|
150 |
4.8 |
0.5 |
110 |
814 |
92 |
389 |
92 |
389 |
11 |
-55 |
23 |
-47 |
23 |
-47 |
872 |
869 |
351 |
||||||||||||||||||||||||||||||||||||||||||
|
200 |
4.3 |
0.6 |
119 |
877 |
97 |
414 |
97 |
414 |
3 |
-16 |
15 |
-30 |
15 |
-30 |
888 |
893 |
346 |
||||||||||||||||||||||||||||||||||||||||||
|
250 |
3.8 |
0.7 |
122 |
900 |
102 |
434 |
102 |
434 |
0 |
-1 |
9 |
-18 |
9 |
-18 |
904 |
901 |
344 |
||||||||||||||||||||||||||||||||||||||||||
___________________
Port
is the port rotor and Star is the starboard rotor.Violet color represents forces and moments on port side of craft.
Red represents forces and moments on starboard side of craft.
PORT
is the sum of the positive rolling moment and STAR is the sum of the negative rolling moment. They must be in balance.The collective and the 3P-amplitude have been adjusted as the forward velocity increases so as to maintain a constant thrust, plus no rolling moment.
So far it appears that the 3rd harmonic (swashring) only needs a maximum amplitude of 0.7º.
___________________
The following is the same as the previous table excepted that it checks the roll moment at the 150-mph conditions, when the blades are at a different azimuth.
MPH:
| Collective: | 3P amplitude: | Blade Segment Thrust @ .75R at Noted Azimuth and Rotor: | Moments: | Total Lift:|
MPH: |
θ 0 |
θ 3P |
105º |
Port |
45º |
Star |
165º |
Star |
285º |
Star |
225º |
Port |
345º |
Port |
PORT |
STAR |
Total Lift: |
||||||||||||||||||||||||||||||||||||||||||
|
|
|
|
lbs |
lb-ft |
lbs |
lb-ft |
lb |
lb-ft |
lbs |
lb-ft |
lbs |
lb-ft |
lbs |
lb-ft |
Port |
Star |
|
||||||||||||||||||||||||||||||||||||||||||
|
150 |
4.8 |
0.5 |
111 |
797 |
105 |
587 |
71 |
195 |
11 |
-55 |
17 |
-56 |
34 |
-16 |
854 |
852 |
349 |
||||||||||||||||||||||||||||||||||||||||||
Looks good!
None of the forgoing yet considers forward cyclic on the rotors.
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Reference:
Advancing Blade Concept (ABC) Dynamics ~ Vibration, page 5 onward ~ Presentation May 1977
Advancing Blade Concept (ABC) High Speed Development ~ Vibration, page 10-12 ~ Presentation May 1980
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|
OTHER: Aerodynamics - Vibration - Rotor Induced - Higher Harmonic Control |
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|
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DESIGN: UniCopter ~ Control - Flight - Swashring - Fixes Azimuth Overview |
Drawing:
Consider 2P and 4P higher harmonic, as alternative.

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Direction of Rotation:
Objective:
To get a comparative value of the moment about the craft's roll axis, based upon the direction of rotor rotation (i.e. outside-forward or inside-forward).
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Conclusion:
The direction of rotation does not change (improve or worsen) the lateral dissymmetry of lift.
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Supporting Calculations:
The craft's rolling moment is positive (+) when it is CW when viewed from the rear.
______________________________________
Rotors Turning Outside-Forward.
|
|
Rotor: |
Azimuth: |
Lift: (pounds) |
Arm: (1) (feet) |
Moment; (ft-lb) |
Direction of Roll: (viewed from aft) |
|
|
Port |
90º |
109.5067 |
7.3725' (88.47") |
807.3384 |
CW |
|
|
Port |
210º |
38.1645 |
2.0048' (24.06") |
-76.5113 |
CCW |
|
|
Port |
330º |
38.1645 |
1.9893' (23.87") |
-75.9194 |
CCW |
|
|
Sum of Port Moments: |
|
|
654.9077 |
CW |
|
|
|
Starboard |
30º |
81.6424 |
4.2496' (50.99") |
-346.9485 |
CCW |
|
|
Starboard |
150º |
81.6424 |
4.2444' (50.93") |
-346.5265 |
CCW |
|
|
Starboard |
270º |
22.5509 |
5.1225' (61.47") |
115.5169 |
CW |
|
|
Sum of Starboard Moments: |
|
|
-577.9581 |
CCW |
|
|
|
Resultant Moment: |
|
|
76.9496 |
CW |
|
(1) The Arm values are back calculated from the Access generated Lift and Moment.
______________________________________
Rotors Turning Inside-Forward.
This table is the above table with values switched so as to represent the crafts moment about its X-axis if the blades were rotating inside-forward.
|
|
Rotor: |
Azimuth: |
Lift: (pounds) |
Arm: (1) (feet) |
Moment; (ft-lb) |
Direction of Roll: (viewed from aft) |
|
|
Port |
30º |
81.6424 |
1.9893' (23.87") |
-162.4112 |
CCW |
|
|
Port |
150º |
81.6424 |
2.0048' (24.06") |
-163.6757 |
CCW |
|
|
Port |
270º |
22.5509 |
7.3725' (88.47") |
166.2565 |
CW |
|
|
Sum of Port Moments: |
|
|
-159.8304 |
CCW |
|
|
|
Starboard |
90º |
109.5067 |
5.1225' (61.47") |
560.9481 |
CW |
|
|
Starboard |
210º |
38.1645 |
4.2444' (50.93") |
-161.9854 |
CCW |
|
|
Starboard |
330º |
38.1645 |
4.2496' (50.99") |
-162.1838 |
CCW |
|
|
Sum of Starboard Moments: |
|
|
237.7789 |
CW |
|
|
|
Resultant Moment: |
|
|
77.9485 |
CW |
|
![]()
Comparison with Coaxial
Objective:
To compare the above two intermeshing roll moments with that of an identical coaxial configuration.
![]()
Conclusion:
All three rotor configurations have the same lateral dissymmetry of lift (moment).
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Rotors Crossing at 90º - 270º:
|
|
Rotor: |
Azimuth: |
Lift: (pounds) |
Arm: (1) (feet) |
Moment; (ft-lb) |
Direction of Roll: (viewed from aft) |
|
|
Lower |
90º |
109.5067 |
6. 25' |
684.4169 |
CW |
|
|
Lower |
210º |
38.1645 |
3.125' |
-119.2641 |
CCW |
|
|
Lower |
330º |
38.1645 |
3.125' |
-191.2641 |
CCW |
|
|
Sum of Lower Moments: |
|
|
301.8887 |
CW |
|
|
|
Upper |
30º |
81.6424 |
3.125' |
-255.1325 |
CCW |
|
|
Upper |
150º |
81.6424 |
3.125' |
-255.1325 |
CCW |
|
|
Upper |
270º |
22.5509 |
6.25' |
140.9432 |
CW |
|
|
Sum of Upper Moments: |
|
|
-369.3219 |
CCW |
|
|
|
Resultant Moment: |
|
|
67.4332 |
CW |
|
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Vibration:
Lockheed XH-51A article from the Nov 2004 issue of Stu Field's magazine Experimental Helo
The rotor head was of a "hinge-less" design. Prouty further states, the "hinge-less" design suffers from the characterization that "they all shook". Lockheed added a fourth blade and controlled the shaking to a more pilot acceptable level.
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Additional Information:
Advancing Blade Concept (ABC) High Speed Development ~ Vibration, page 10-12 ~ Presentation May 1980
See also:
OTHER: Aerodynamics - General - Cross-couplingSee notes on:
DESIGN: UniCopter ~ Rotor Disk - Absolutely Rigid Rotor![]()
Introduction Page | SynchroLite Home Page | Electrotor Home Page | UniCopter Home Page | Nemesis Home Page | AeroVantage Home Page:
Last Revised: August 12, 2008