Item 0871

DESIGN: UniCopter ~ Rotor - Disk - Lateral Dissymmetry of Lift and Drag? - (3-blades)

Review 1073.html in Obsolete folder to see if these two pages are in agreement

Overview:

Evaluation of the oscillating rolling moments with two 3-blade really rigid rotors, during forward flight, caused by dissymmetry of lift.

Conclusion:

There will be vibration, with 3-blade rotors. The side of the helicopter that has the advancing blade located at 90º azimuth will have greater lift than the other side where the advancing blades are at 30º and 150º azimuth. This is irrespective of whether the rotation is outside-forward or inside-forward.

Potential Solutions:

Evaluation of the oscillating yawing moments during forward flight, caused by the dissymmetry of H-force drag, may be later considered on a separate web page.

Drawing of Lateral Moment Arms of a Single Rotor:

 

Hover:

Moment on Y-Y: (100 lbs. * 1.0) = (2 * ( 100 lbs. * .5))

If all three blades are providing an equal amount of lift then the center of the lift will be at the centerline of the disk. Brilliant; I didn't need a drawing to prove this.

_____________________________

Perhaps the significance of this is that if the center of lift is behind the centerline of the blade's pitch axis then the blades will be imparting a loading on the pitch arms. During hover, there should be no cyclic oscillation because the sum of the moments of the three blades should equal zero. There will be a force on the collective.

The center of lift on the VR7 blade varies from 41% of chord at Alpha = 0º to 29.3% of chord at Alpha = 12º.

This page was done to assure that the wheels in the 'swash-ring' are always in contact with the same flange of the ring and therefore not having to change their direction of rotation ( at 600 RRPM) 40 times per second. They will contact both flanges if Higher Harmonic Control is implemented. See swishring with revision for one torus with a follower on the top and a follower on the bottom.

Forward Flight: (Lateral Dissymmetry of Lift and Drag)

I think that the single advancing blade at 90º azimuth will have a greater thrust than the other rotor's two advancing blades which will be at 30º and 150º azimuth, Note the moment arm lengths and the air velocity. This will cause a rotational vibration about the longitudinal axis (roll). Higher Harmonic Control will allow the lift at 30º and 150º azimuth to be increase somewhat and the lift at 90º azimuth to be decrease somewhat.

Flight-Control Solution:

Consider adjusting HHC pitch by a spring steel 'warpable' swishring. Adjust by heat (bimetal), electrical (magnet) or mechanically.

The 1P will involve frequent changes, as the cyclic stick is moved. Changes to the HHC will be gradual and infrequent, relative to the primary control, since it is controlled by the forward velocity of the craft. The 3P control may be similar to the SynchroLite's Opposed Lateral Cyclic. For possible means of flight control, see DESIGN: UniCopter ~ Control - Flight - Swishring - Fixed Azimuth Overview

Re Drag: An airfoil that has a higher cl/cd than another should have a lower dissymmetry of drag for a given lift.

Calculations: by   FORM: Lateral Dissymmetry ~ UniCopter

Default Values:

Slope of lift chord: a = 6.0 / radian

Vertical velocity in hover: v1 = 25 fps

Density: ρ = 0.002377 slug/ft3 @ ISA

Rotor: Ω = 600 RPM

Radius: r = 0.75 * 8.33 = 6.2475 feet

Chord: c = 0.666 feet

Blade segment Δr = (8.33 / 10) = 0.833 feet

Collective = 5.5º

Inputs:

Collective: θ0

1P Blade Pitch θ1P, Azimuth of input blade pitch: Ψ1P.

Higher harmonic 3P blade pitch: θ3P.

Forward Velocity: V

Cyclic amplitude: θ1P

Cyclic amplitude azimuth: Ψ1P

3rd harmonic amplitude: θ3P

Algorithims:

Tangential (local) Velocity: U = (Ω * r) + V * sin(Ψ * ( π / 180) [ft/sec]

Inflow Angle: φ = v1 / (U) [radians]

Cyclic amplitude at azimuth: θ1P = θ1P * sin(Ψ1P) This will have to be checked.

3rd harmonic amplitude at azimuth: θ3P = θ3P * sin(Ψ * 3) This will have to be checked.

Blade Pitch: θ = θ1P + θ3P

Blade Pitch: θ = ά + φ [radians]

Angle of Attack: ά = θ - φ [radians]

Lift [L]:

An aerodynamic force caused by air flowing over an airfoil. The vertical component of thrust.

For an airplane wing: LW = (ρ / 2) * V2 * CL * S . Where S is the area of the wing.

 

ΔL = (ρ / 2) * (Ω * r)2 * a(θ - (v1 / (Ω * r)) * c * Δr

ΔL = (ρ / 2) * (U)2 * a(θ - (v1 / U)) * c * Δr

ΔL = (ρ / 2) * (U)2 * a(θ - φ) * c * Δr

ΔL = (0.002377 / 2) * (U)2 * a(θ - φ) * 0.666 * 0.833

ΔL = 0.001188 * (U)2 * a(θ - φ) * 0.666 * 0.833

L = (U)2 * a(θ - φ) * 0.000659

 

Thoughts on coding:

Base calculations on r = .75R at all azimuths, even though it will be greater on the retreating side.

  FORM: Lateral Dissymmetry ~ UniCopter

The following values assume that the rotor disks have no forward pitch and all the forward thrust is coming from a pusher propeller.

The following thrust values are only for the blade segment at .75R of a helicopter weighing 750 lb GW and are probably not representative of the whole blade.

MPH: | Collective: | 3P amplitude: | Blade Segment Thrust @ .75R at Noted Azimuth and Rotor: | Moments: | Total Lift:

MPH:

θ0

θ3P

90º

Port

30º

Star

150º

Star

270º

Star

210º

Port

330º

Port

PORT

STAR

Total Lift:

 

 

 

lbs

lb-ft

lbs

lb-ft

lb

lb-ft

lbs

lb-ft

lbs

lb-ft

lbs

lb-ft

Port

Star

 

0

5.5

0

58

427

58

246

58

246

58

-296

58

-116

58

-116

724

723

348

50

5.4

0.1

79

580

69

 294

69

 294

38

 -195

46

 -92

46

 -92

772

775

347

100

5.1

0.3

95

704

80

341

80

341

22

-113

33

-67

33

-67

816

817

343

150

4.8

0.5

110

814

92

389

92

389

11

-55

23

-47

23

-47

872

869

351

200

4.3

0.6

119

877

97

414

97

414

3

-16

15

-30

15

-30

888

893

346

250

3.8

0.7

122

900

102

434

102

434

0

-1

9

-18

9

-18

904

901

344

___________________

Port is the port rotor and Star is the starboard rotor.

Violet color represents forces and moments on port side of craft.

Red represents forces and moments on starboard side of craft.

PORT is the sum of the positive rolling moment and STAR is the sum of the negative rolling moment. They must be in balance.

The collective and the 3P-amplitude have been adjusted as the forward velocity increases so as to maintain a constant thrust, plus no rolling moment.

So far it appears that the 3rd harmonic (swashring) only needs a maximum amplitude of 0.7º.

___________________

The following is the same as the previous table excepted that it checks the roll moment at the 150-mph conditions, when the blades are at a different azimuth.

MPH: | Collective: | 3P amplitude: | Blade Segment Thrust @ .75R at Noted Azimuth and Rotor: | Moments: | Total Lift:

MPH:

θ0

θ3P

105º

Port

45º

Star

165º

Star

285º

Star

225º

Port

345º

Port

PORT

STAR

Total Lift:

 

 

 

lbs

lb-ft

lbs

lb-ft

lb

lb-ft

lbs

lb-ft

lbs

lb-ft

lbs

lb-ft

Port

Star

 

150

4.8

0.5

111

797

105

587

71

195

11

-55

17

-56

34

-16

854

852

349

Looks good!

None of the forgoing yet considers forward cyclic on the rotors.

Reference:

Advancing Blade Concept (ABC) Dynamics ~ Vibration, page 5 onward ~ Presentation May 1977

Advancing Blade Concept (ABC) High Speed Development ~ Vibration, page 10-12 ~ Presentation May 1980

 

OTHER: Aerodynamics - Vibration - Rotor Induced - Higher Harmonic Control

0793

 

DESIGN: UniCopter ~ Control - Flight - Swashring - Fixes Azimuth Overview

1092

 Drawing:

Consider 2P and 4P higher harmonic, as alternative.

Direction of Rotation:

Objective:

To get a comparative value of the moment about the craft's roll axis, based upon the direction of rotor rotation (i.e. outside-forward or inside-forward).

Conclusion:

The direction of rotation does not change (improve or worsen) the lateral dissymmetry of lift.

Supporting Calculations:

The craft's rolling moment is positive (+) when it is CW when viewed from the rear.

______________________________________

Rotors Turning Outside-Forward.

 

Rotor:

Azimuth:

Lift: (pounds)

Arm: (1) (feet)

Moment; (ft-lb)

Direction of Roll: (viewed from aft)

 

Port

90º

109.5067

7.3725' (88.47")

807.3384

CW

 

Port

210º

38.1645

2.0048' (24.06")

-76.5113

CCW

 

Port

330º

38.1645

1.9893' (23.87")

-75.9194

CCW

 

Sum of Port Moments:

 

 

654.9077

CW

 

Starboard

30º

81.6424

4.2496' (50.99")

-346.9485

CCW

 

Starboard

150º

81.6424

4.2444' (50.93")

-346.5265

CCW

 

Starboard

270º

22.5509

5.1225' (61.47")

115.5169

CW

 

Sum of Starboard Moments:

 

 

-577.9581

CCW

 

Resultant Moment:

 

 

76.9496

CW

(1) The Arm values are back calculated from the Access generated Lift and Moment.

______________________________________

Rotors Turning Inside-Forward.

This table is the above table with values switched so as to represent the crafts moment about its X-axis if the blades were rotating inside-forward.

 

Rotor:

Azimuth:

Lift: (pounds)

Arm: (1) (feet)

Moment; (ft-lb)

Direction of Roll: (viewed from aft)

 

Port

30º

81.6424

1.9893' (23.87")

-162.4112

CCW

 

Port

150º

81.6424

2.0048' (24.06")

-163.6757

CCW

 

Port

270º

22.5509

7.3725' (88.47")

166.2565

CW

 

Sum of Port Moments:

 

 

-159.8304

CCW

 

Starboard

90º

109.5067

5.1225' (61.47")

560.9481

CW

 

Starboard

210º

38.1645

4.2444' (50.93")

-161.9854

CCW

 

Starboard

330º

38.1645

4.2496' (50.99")

-162.1838

CCW

 

Sum of Starboard Moments:

 

 

237.7789

CW

 

Resultant Moment:

 

 

77.9485

CW

 

Comparison with Coaxial

Objective:

To compare the above two intermeshing roll moments with that of an identical coaxial configuration.

Conclusion:

All three rotor configurations have the same lateral dissymmetry of lift (moment).

Rotors Crossing at 90º - 270º:

 

Rotor:

Azimuth:

Lift: (pounds)

Arm: (1) (feet)

Moment; (ft-lb)

Direction of Roll: (viewed from aft)

 

Lower

90º

109.5067

6. 25'

684.4169

CW

 

Lower

210º

38.1645

3.125'

-119.2641

CCW

 

Lower

330º

38.1645

3.125'

-191.2641

CCW

 

Sum of Lower Moments:

 

 

301.8887

CW

 

Upper

30º

81.6424

3.125'

-255.1325

CCW

 

Upper

150º

81.6424

3.125'

-255.1325

CCW

 

Upper

270º

22.5509

6.25'

140.9432

CW

 

Sum of Upper Moments:

 

 

-369.3219

CCW

 

Resultant Moment:

 

 

67.4332

CW

Vibration:

Lockheed XH-51A article from the Nov 2004 issue of Stu Field's magazine Experimental Helo

The rotor head was of a "hinge-less" design. Prouty further states, the "hinge-less" design suffers from the characterization that "they all shook". Lockheed added a fourth blade and controlled the shaking to a more pilot acceptable level.

 Additional Information:

Advancing Blade Concept (ABC) High Speed Development ~ Vibration, page 10-12 ~ Presentation May 1980

See also: OTHER: Aerodynamics - General - Cross-coupling

See notes on: DESIGN: UniCopter ~ Rotor Disk - Absolutely Rigid Rotor

Introduction Page | SynchroLite Home Page | Electrotor Home Page | UniCopter Home Page | Nemesis Home Page | AeroVantage Home Page:

Last Revised: August 12, 2008